Directions: Each of the questions given below is followed by series of options among which you have to choose the best one. You can also review your choices by clicking into answer section.
16. In a garden, 26 trees are planted at equal distances along a yard 300 meters long, one tree being at each end of the yard. What is the distance between two consecutive trees?
A. 10
B. 20
C. 14
D. 12
Answer
Explanation:
26 trees have 25 gaps between them.
Length of each gap = 300/25 = 12
i.e., distance between two consecutive trees = 12
17. A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsalable and there are 12 unsalable mangoes in the crate then how many mango are there in the crate?
A. 480
B. 460
C. 470
D. 450
Answer
Explanation:
Let the total no of mangoes in the crate be x
Then the no of bruised mango = 1/30 x
Let the no of unsalable mangoes =3/4 (1/30 x)
or, 1/40 x =12
So, x = 480
18. A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
A. 30 birds
B. 60 birds
C. 72 birds
D. 90 birds
Answer
Explanation:
Let the total number of shots be x. Then,
Shots fired by A = 5x/8
Shots fired by B = 3x/8
Killing shots by A = (1/3) of (5x/8)= (5x/24)
Shots missed by B = (½) of (3x/8) = (3x/16)
or, 3x/16= 27
So, X= 144
Birds killed by A = 5x/24 = (5×144)/24 = 30
19. A boy was asked to multiply a number by 22. He instead multiplied the number by 44 and got the answer 308 more than the correct answer. What was the number to be multiplied?
A. 16
B. 10
C. 14
D. 12
Answer
Explanation:
Let the number be x
22x + 308 = 44x
=> 44x – 22x = 308
=> 22x = 308
=> x = 308/22 = 154/11 = 14
20. Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:
A. 1/7
B. 1/8
C. 1/9
D. 7/8
Answer
Explanation:
Original share of 1 person = 1/8
New share of 1 person = 1/7
Increase= (1/7)-(1/8) = 1/56
Required fraction = (1/ 56) x (8/1) = (1/7)
21. There are two buildings P and Q. If 15 persons are sent from P to Q, then the number of persons in each building is the same. If 20 persons are sent from Q to P, then the number of persons in P is double the number of persons in Q. How many persons are there in building P?
A. 80
B. 140
C. 120
D. 90
Answer
Explanation:
Let the number of persons in building P = p and the number of persons in building Q = q
If 15 persons are sent from P to Q, then the number of persons in each building is the same
=> p-15 = q+15
=> p – q = 30 —-(Equation 1)
If 20 persons are sent from Q to P, then the number of persons in P is double the number of persons in Q
=> 2(q – 20) = (p + 20)
=> 2q – 40 = p + 20
=> 2q – p = 60 —-(Equation 2)
(Equation 1) + (Equation 2) => q = 90
From Equation 1, p = 30 + q
=30 + 90
= 120
i.e., Building P has 120 persons
22.The price of 3 tables and 4 chairs is Rs.3300. With the same money one can buy 2 tables and 10 chairs. If one wants to buy 1 table and 1 chair, how much does he need to pay?
A. Rs.940
B. Rs.1050
C. Rs.1040
D. None of the above
Answer
Explanation:
Let price of a table = t and price of a chair = c
3t + 4c = 3300 — (Equation 1)
2t + 10c = 3300
=> t + 5c = 1650 — (Equation 2)
(Equation 2) × 3 => 3t + 15c = 4950 — (Equation 3)
(Equation 3) – (Equation 1) => 11c = 1650
=> c = 150
Substituting the value of c in equation 1, we get
3t + (4 × 150) = 3300
=> 3t = 3300 – 600 = 2700
=>t = 2700/3 = 900
Cost of 1 table and 1 chair = c + t = 150 + 900 = 1050
