Directions: Each of the questions given below is followed by series of options among which you have to choose the best one. You can also review your choices by clicking into answer section.
31. What is the unit digit in (795 – 358)?
A.0
B.4
C.6
D.7
Answer
Explanation:
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3
Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9
Unit digit in (795 – 358) = Unit digit in (343 – 9) = Unit digit in (334) = 4.
So, Option B is the answer.
32. If a and b are odd numbers, then which of the following is even?
A.a + b
B.a + b + 1
C.ab
D.ab + 2
Answer
Explanation:
The sum of two odd numbers is even. So, a + b is even.
33. (35423 + 7164 + 41720) – (317 x 89)= ?
A.28213
B.84307
C.50694
D.56094
E.None of these
Answer
Explanation:
35423 317 x 89 = 317 x (90 -1 )
+ 7164 = (317 x 90 – 317)
+ 41720 = (28530 – 317)
—– = 28213
84307
– 28213
—–
56094
—–
34. Which one of the following is the common factor of (4743 + 4343) and (4747 + 4347)?
A. (47 – 43)
B.(4743 + 4343)
C.(47 + 43)
D. None of these
Answer
Explanation:
No explanation
35. Which of the following numbers is divisible by each one of 3, 7, 9 and 11 ?
A.639
B.2079
C.3791
D.37911
E.None of these
Answer
Explanation:
639 is not divisible by 7
2079 is divisible by each of 3, 7, 9, 11.
36. A number when divided by 119 leaves 19 as remainder. If the same number is divided, by 17, the remainder obtained is.
A.10
B. 3
C. 7
D.2
Answer
Explanation:
Let the given number when divided by 119 give k as quotient and 19 as remainder. Then,
Given number = 119k + 19
=17 * 7k + 17 + 2= 17(7k + 1) + 2.
So, the given number when divided by 17 gives (7k + 1) as quotient and 2 as remainder.
37. How many prime numbers are less than 50?
A.16
B.15
C.14
D.18
Answer
Explanation:
Prime numbers less than 50 are:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47
Their number is 15
38. What is the largest 4 digit number exactly divisible by 88?
A. 9944
B. 9999
C. 9988
D. 9900
Answer
Explanation:
Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88 = 9999 – 55 = 9944
39. 9 + 3/4 + 7 + 2/17 – ( 9 + 1/15)= ?
A. 7+(719/1020)
B.9+(817/1020)
C.9+(719/1020)
D.7+(817/1020)
E. None of these
Answer
Explanation:
No explanation
40.If a/b=1/3,b/c=2,c/d=1/2,d/e=3,e/f=1/4 then what is the value of abc/def ??
A. 3/8`
B. 27/8
C. 3/4
D. 27/4
Answer
Explanation:
a/b=1/3,b/c
a : b : c = 2 : 6 : 3
Similarly a : b : c : d : e : f = 6 : 18 : 9 : 18 : 6 : 24
abc/def=(6x18x9)/(18x6x24)=3/8
41. If the number 5 * 2 is divisible by 6, then * =?
A.2
B.3
C.6
D.7
Answer
Explanation:
6 = 3 x 2. Clearly, 5 * 2 is divisible by 2. Replace * by x.
Then, (5 + x + 2) must be divisible by 3. So, x = 2.
42. Find the number of numbers between 200 and 300,both included, which are not divisible by 2,3,4,and 5 ?
A. 27
B. 26
C. 25
D. 28
Answer
Explanation:
Use the principal of counting , Start with 101 numbers (i.e. all numbers between 200 and 300 both includeD. and subtract the number of numbers which are divisible by 2 (viz. [(300-200)/2]+1=51 numbers).The number of numbers which are divisible by 3 but not by 2 (note: this would be given by the number of terms in the series 201,207, …… 297 and this series has 17 terms) and the number which are divisible by 5 but not by 2 and 3. (The numbers are 205,215,235,245,265,275,295 i.e, total of 7 numbers). Thus, the required answer is given by 101-51-17-7=26.
43. In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend?
A.4236
B.4306
C.4336
D.5336
E.None of these
Answer
Explanation:
Divisor = (5 x 46) = 230
10 x Quotient = 230 = 230/10 = 23
Dividend = (Divisor x Quotient) + Remainder
= (230 x 23) + 46
= 5290 + 46
= 5336.
44. How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed?
A. 499
B. 500
C. 375
D. 376
Answer
Explanation:
The minimum number that can be formed is 1000 and the maximum number that can be formed is 4000.
As 4000 is the only number in which the first digit is 4,
First let us calculate the numbers less than 4000 and then we will add 1 to it.
First digit can be 1, 2 or 3.
Remaining 3 digits can be any of the 5 digits.
Total numbers that can be formed, which are less than 4000 = 3 × 5 × 5 × 5 = 375
Total numbers that satisfy the given condition
= 375 + 1 = 376
Hence, option 4 is correct.
45. How many of the following numbers are divisible by 3 but not by 9?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276
A.5
B.6
C.7
D.None of these
Answer
Explanation:
Marking (/) those which are divisible by 3 by not by 9 and the others by (X), by taking the sum of digits, we get is
2133 9 (X)
2343 12 (/)
3474 18 (X)
4131 9 (X)
5286 21 (/)
5340 12 (/)
6336 18 (X)
7347 21 (/)
8115 15 (/)
9276 24 (/)
Required number of numbers = 6.
