Directions: Each of the questions given below is followed by series of options among which you have to choose the best one. You can also review your choices by clicking into answer section.
16. The present age of a ram is 3 years more than three times the age of his Shyam. Three years hence, ram age will be 10 years more than twice the age of the Shyam. What is Ram present age?
A. 30 years
B. 31 years
C. 32 years
D. 33 years
Answer
Explanation:
Let the present age the Shyam = x.
Then present age of the Ram = 3x + 3
Given that, three years hence, ram age will be 10 years more than twice the age of the Shyam
(3x+3+3) = 2(x + 3) +10
x = 10
Ram's present age = 3x + 3 = 3×10+ 3 = 33
17. The ratio of present age of X and Y is 11:20 respectively. Seven years ago, X was 5/11 of Y in age. Find the difference between their present ages.
A. 15
B. 30
C. 22
D. 18
Answer
Explanation:
Let the ages of X and Y, 7 years ago be 5a/11 years and a years respectively.
Then, (5a/11 + 7)/(a+7) = 11/20
20(5a/11 + 7) = 11(a+7)
100a/11 + 140 = 11a + 77
21a = 693
a = 33
Therefore, the difference between their present ages = (a+7) – (5a/11 + 7) = 40 – 22 = 18.
18. The average age of two brothers in a family is 21. The average drops to 19 when the age of the third brother is also included.Find the age of the third brother.
A. 18
B. 19
C. 15
D. 21
Answer
Explanation:
Let the ages of the three brothers be x, y and z.
Average age of two brothers
(x+y)/2 = 21
x+y=42
Average drops when age of third brother is included
(x+y+z)/3=19
x+y+z=57
Now by putting the value of x+y=42
42+z=57
z=15,
So, the age of third brother is 15 years.
19. At present, the ratio between the ages of Arun and Deepesh is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepesh at present?
A. 12 years
B. 15 years
C. 19 and half
D. 21 years
Answer
Explanation:
Let the present ages of Arun and Deepesh be 4x years and 3x years respectively. Then,
4x + 6 = 26
4x = 20
x = 5.
Deepesh's age = 3x = 15 years.
20. Neharika is 9 years older than Anisha. Two years ago, Anisha's age was half that of Neharika's. Find Anisha's present age.
A. 10
B. 11
C. 15
D. 18
Answer
Explanation:
Suppose the age of Neharika is N
And the age of Anisha is A
First euation,
N=A+9
Second equation,
(A-2)=(1/2)*(N-2)
2A-4=N-2
Now, substituting value of N from first equation to second equation we get
2A-4 = A+9-2
A = 11
21. Sandeep's age after six years will be three-seventh of his father's age. Ten years ago the ratio of their ages was 1 : 5. What is Sandeep's father's age at present?
A. 30 years
B. 40 years
C. 50 years
D. 60 years
Answer
Explanation:
Let the age of Sandeep and his father before 10 years be x and 5x respectively.
Given that Sandeep's age after six years will be three-seventh of his father's age
x + 16 = (3/7)(5x + 16)
7x + 112 = 15x + 48
8x = 64
x = 8
Sandeep's father's present age = 5x + 10 = 5×8 + 10 = 50.
22. Today is Anish's birthday. One year from today, he will be twice as old as he was 10 years ago. How old is Anish today?
A. 21 years
B. 23 years
C. 22 years
D. 25 years
Answer
Explanation:
Let his present age be x.
His age after one years
x+1
His age before 10 years
x-10
According to question,
x+1 = 2(x-10)
On Solving we get , x = 21
So Anish is 21 years old
23. Alaka's age is 1/6th of her father's age. Alaka's father's age will be twice the age of Saugat's age after 10 years. If Saugat's eight birthdays was celebrated two years before, then what is Alaka's present age.
A. 10 years
B. 12 years
C. 8 years
D. 5 years
Answer
Explanation:
Consider Alaka's present age = x
Then her father's age = 6x
Given that Alaka's father's age will be twice the age of Saugat's age after 10 years
Saugat's age after 10 years = (1/2)(6x + 10) = 3x + 5
Also given that Saugat's eight birthdays was celebrated two years before
Saugat's age after 10 years = 8 + 12 = 20
3x + 5 = 20
x = 15/3
x = 5
Therefore, Alaka's present age = 5 years
24. The total ages of Jyant, Prem and Saransh is 93 years. Ten years ago ,the ratio of their ages was 2:3:4. What is thepresent age of Saransh?
A. 24 years
B. 32 years
C. 34 years
D. 38 years
Answer
Explanation:
Let the ages of jayant, prem and saransh 10 years ago be 2x, 3x and 4x years respectively.
Then, (2x+10)+(3x+10)+(4x+10)=93
=> 9x=63
=> x=7
Therefore, Saransh's present age=(4x+10)= 38 years
25. A person's present age is two fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
A. 32 years
B. 36 years
C. 40 years
D. 48 years
Answer
Explanation:
Let the mother's present age be X years. Then, person’s present age= (2/5x) years.
Therefore (2/5x+8)=1/2(x+8)
2(2x+40)=5(x+8)
x=40
26. Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
A. 20 years
B. 30 years
C. 45 years
D. None of these
Answer
Explanation:
Let the ages of A and B 10 years ago be x and 2x years respectively.
Then, (x+10)÷(2x+10)=3/4
4(x+10)=3(2x+10)
2x=10
x=5
Therefore sum of their present ages=(x+10)+(2x+10)=(3x+20)=35 years
27. Six years ago, the ratio of the ages of Bivek and Saroj was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Saroj's age at present?
A. 18
B. 17
C. 16
D. 15
Answer
Explanation:
Given that, six years ago, the ratio of the ages of Bivek and Saroj = 6 : 5
Hence we can assume that
Age of Bivek six years ago = 6x
Age of Saroj six years ago = 5x
After 4 years, the ratio of their ages = 11 : 10
(6x+10) : (5x + 10) = 11 : 10
10(6x + 10) = 11(5x + 10)
5x = 10
x = 105 = 2
Saroj's present age = 5x + 6 = 5×2 +6 = 16
28. The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A. 8, 20, 28
B. 16, 28, 36
C. 20, 35, 45
D. None of these
Answer
Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
29.Himal is 40 years old and Rochak is 60 years old.How many years ago was the ratio of their ages 3:5?
A. 5 years
B. 10 years
C. 20 years
D. 37 years
Answer
Explanation:
Suppose, the ratio was 3:5, x years ago.
Then, (40-x)÷(60-x)=3/5
=> 5(40-x)=3(60-x)
=>2x=20
x=10
30. A man's age is 125% of what it was 10 years ago, but 831/3 % of what it will be after ten 10 years. What is his present age?
A. 70
B. 60
C. 50
D. 40
Answer
Explanation:
Let the age before 10 years = x
Then 125×100 = x + 10
125x = 100x + 1000
x = 1000÷25 = 40
Present age = x + 10 = 40 +10 = 50
